Three vertices are chosen randomly from the seven vertices of a regular `7`-sided polygon. The probability that they form the vertices of an isosceles triangle is

Three vertices are chosen randomly from the seven vertices of a regular 7-sided polygon. The probability that they from the vertices of an isosceles triangle is-

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle with these vertices is an equilateral triangle is equal to

Three vertices are chosen from the vertices of a regular hexagon,then the probability that they will form an equilateral triangle is

Three distinct vertices are chosen at random from the vertices of a given regular polygon of (2n + 1) sides Let all such choices are equally likely and the probability that the centre of the given polygon lies in the interior of the triangle determined by these three chosen random points is 5/14 Three vertices of the polygon are chosen at random. The probability that these vertices form an isosceles triangle is.

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly two sides common with the side of the hexagon is

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly two sides common with the side of the hexagon is

Three vertices are chosen at random from the vertices of a regular hexagon then The probability that the triangle has exactly one side common with the side of the hexagon is

Three distinct vertices are randomly chosen among the vertices of a cube. The probability that they from equilateral triangle is

Three of six vertices of a regular hexagon are chosen at random. Tie probability that the triangle formed by these vertices is an equilateral triangle is