A particle is moving such that its position coordinates `(x, y)` are `(2m, 3m)` at time `t=0, (6m, 7m)` at time `t=2 s`, and `(13 m, 14m)` at time `t=5 s`.
Average velocity vector`(vec(V)_(av))` from `t=0` to `t=5 s` is

A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t=0 . (6m, 7m) at time t= 2 s and (13m, 14m) at time t=5 s Average velocity vector from 0s to 5 s is

A particle is moving such that its position coordinates (x,y) are (2m,3m) at time t=0 , (6m,7m) at time t=2s and (13m 14m) at time t=5s. Average velocity vector (vecV_(av)) from t=0 to t=5s is

A particle is moving such that its position coordinates (x,y) are (2m,3m) at time t=0 , (6m,7m) at time t=2s Average velocity vectors (V_av) from t=0 to t=5 s is :

A particle is moving such that its position coordinates (x,y) are (2m,3m) at time t=0,(13m,14m) at time t=5s .Average velocity vector from t =0 to t=5s

A particle is moving with uniform acceleration. Its position (x) is given in terms of time (t in s) as X =(5t2+4t+8)m ,then

A particle is moving along x-axis such that its velocity varies with time according to v=(3m//s^(2))t-(2m//s^(3))t^(2) . Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.

A particle is moving along x-axis such that its velocity varies with time according to v=(3m//s^(2))t-(2m//s^(3))t^(2) . Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.

A particle is moving on a straight line. Its velocity at time t is (8-2t)m//s . What is the total distance covered from t=0 to t=6s ?