If `cos theta=-1/2` and `0^@ < theta < 360^@` then the solutions are `a. 60^@, 240^@, b.120^@, 240^@, c.120^@, 210^@, d.120^@, 300^@`

Fill in the blanks : tan theta=sqrt(3), cos theta= -(1)/(2) and 0^(@) lt theta lt 360^(@) , then theta= _______________ .

If (3sin2theta)/(1-cos2theta)=1/2 and 0^(@)letheta180^(@) , then theta =

The number of solution of the equation sin theta cos theta cos 2 theta .cos 4theta =1/2 in the interval [0,pi]

The number of solution of the equation sin theta cos theta cos 2 theta .cos 4theta =1/2 in the interval [0,pi]

If 5 cos^2 theta+1=3 sin^2, 0^@ यदि 5 cos^2 theta+1=3 sin^2, 0^@< theta< 90^@ ,है, तो (tan theta+ sec theta)/(cot theta+cosec theta) का मान क्या होगा :

The number of solutions of equation 3cos2 theta+5cos theta=1 in [0,2 pi] is

If 2cos^(2)theta-1=0andtheta is acute then what is the value of (cot^(2)theta-tan^(2)theta) ?

If 2cos theta - sin theta = 1/sqrt(2), (0^(@) lt theta lt 90^(@)) then the value of 2sin theta + cos theta is:

If cos theta cos 2 theta cos 3theta = 1//4 for 0 lt theta lt pi then theta =

Solve cos theta * cos 2 theta * cos 3 theta = (1)/( 4), 0 le theta le pi