The bob of a simple pendulum is displaced from its equilibrium position 'O' to a position 'Q' which is at a height 'h' above 'O' and the bob is then released. Assuming the mass of the bob to be 'm' and time period of oscillation to be `2.0s`, the tension in the string when the bob passes through 'O' is

The bob of a simple pendulum it displaced position O to a equilibrium position Q which is at height it above O and the bob to then mass reklaesed Assuming the mass of the bob to be a and 2.0 sec of oscilation to be string when the bob pases through O is

A simple pendulum of length l and bob of mass m is displaced from its equilibrium position O to a position P so that hight of P above O is h . If is then released. What is the tension in the string when the bob passes through the through the equilibrium position O ? Neglect friction. v is the velocity of the bob at O

A simple pendulum of length l and bob of mass m is displaced from its equilibrium position O to a position P so that hight of P above O is h . If is then released. What is the tension in the string when the bob passes through the through the equilibrium position O ? Neglect friction. v is the velocity of the bob at O

The bob of a simple pendulum of length 1 m is' pulled aside from its equilibrium’ position through an angle 60^@ and released. Calculate the speed at which the bob passes the equilibrium position.

The bob of pendulum of length l is pulled aside from its equilibrium position through an angle theta and then released. Find the speed v with which the bob passes through the equilibrium position.

The string of a pendulum is horizontal. The mass of the bob is m. Now the string is released. The tension in the string in the lowest position is -