The angular momentum of a flywheel having a moment of inertia of ` 0.4 kg m^(2)` decreases from 30 to 20 ` kg m^(2)//s` in a period of 2 second. The average torque acting on the flywheel during this period is :

The angular momentum of a flywheel having a rotational inertia of 0.140kg*m^(2) about its central axis decreases from 3.00 to 0.800kg*m^(2)//s in 1.50 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? ( c) How much work is done on the wheel? (d) What is the average power of the flywheel?

the angular acceleration of flywheel having moment of inertia 50 kg m^2 when a torque of 5 N-m is applied on the flywheel is

the angular acceleration of flywheel having moment of inertia 50 kg m^2 when a torque of 5 N-m is applied on the flywheel is

The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg m^(2)s^(-1) is 2 seconds. Calcualte the torque acting on the particle

The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg m^(2)s^(-1) is 2 seconds. Calcualte the torque acting on the particle

The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg m^(2)s^(-1) is 2 seconds. Calcualte the torque acting on the particle

A flywheel of moment of inertia 2 "kg-m"^(2) is rotated at a speed of 30 "rad/s" . A tangential force at the rim stops the wheel in 15 second. Average torque of the force is

A flywheel of moment of inertia 2 "kg-m"^(2) is rotated at a speed of 30 "rad/s" . A tangential force at the rim stops the wheel in 15 second. Average torque of the force is