सिद्ध कीजिए कि
` sin A sin ( B-C) + sin B sin (C-A) `
` + sin C sin (A-B)=0`

Show that: sin A sin(B-C)+sin B sin(C-A)+sin C sin(A-B)=0

show that sin A*sin(B-C)+sin B*sin(C-A)+sin C*sin(A-B)=0

In a DeltaABC , prove that : sin3A sin(B-C)+sin3B sin(C-A) + sin3C sin (A-B)=0 .

a sin A-b sin B=c sin(A-B)

a sin A-b sin B=c sin(A-B)

a sin A-b sin B=c sin(A-B)

If p = sin (A-B) sin (C-D) q = sin (B-C) sin (A-D) , r = sin (C-A) sin (B- D) then

Prove that (sin (A - B))/( sin A sin B ) + ( sin (B -C))/( sin B sin C ) + (sin (C - A))/( sin C sin A) =0

sin (B + CA) + sin (C + AC) + sin (A + BC) = 4sin A sin B sin C

Simplify: sin (B + C) sin (B - C) + sin (C + A) sin (C - A) + sin(A + B) sin (A - B)