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Mass action ratio or reaction quotient Q...

Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass actionl,
`A(g)+B(g)hArrC(g)+D(g)`
`Q=([C][D])/([A][B])`
The value of Q decides whether the reaction is at equilibrium or not.
At equilibrium, Q=K
For non-equilibrium process `QneK`
When `QgtK`, reaction will be favoured in backward direction and when `QltK`, it will be favoured in forward direction. In a reaction mixture containing `H_(2),N_(2)` and `NH_(3)` at partial pressure of 2 atm, 1 atm and 3 atm respectively, the value of `K_(p)` at 725 K is `4.28xx10^(-5)` `"atm"^(-2)`. In which direction the net reaction will go ?
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`

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Mass action rato or reaction quotient Q for a reaction can be calculate using the law of masss action A(g)+B(g) hArr C(g)+D(g) Q=([C][D])/([A][B]) The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q=K For an equilibrium process, Q ne K when Q gt K , reaction will favour backward direction and when Q lt K , it will favour forward direction. Answer the following questions: In a reaction mixture containing H_(2), N_(2) and NH_(3) at partial pressure of 2 atm, 1 atm and 3 atm respectively, the value of K_(p) at 700 K is 4.00xx10^(-5) atm^(-2) . In which direction the net reaction will go? N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)

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Mass action rato or reaction quotient Q for a reaction can be calculate using the law of masss action A(g)+B(g) hArr C(g)+D(g) Q=([C][D])/([A][B]) The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q=K For an equilibrium process, Q ne K when Q gt K , reaction will favour backward direction and when Q lt K , it will favour direction. Answer the following questions: In a reaction mixture containing H_(2), N_(2) and NH_(3) at partial pressure of 2 atm, 1 atm and 3 atm respectively, the value of K_(p) at 700 K is 4.00xx10^(-5) atm^(-2) . In which direction the net reaction will go? N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)

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