The amount of force needed to pull out a regular hexagonal figure made of wire, perpendicular to its plane from liquid of surface tension 'T' will be :-
(assume mass of wire is m, side = a)

A square wire frame of side / is floating on the surface of liquid of surface tension T. The force required to pull out the frame from the liquid is

A square wire frame of side / is floating on the surface of liquid of surface tension T. The force required to pull out the frame from the liquid is

A current (I) carrying circular wire of radius R is placed in a magnetic field B perpendicular to its plane. The tension T along the circumference of the wire is

A current (I) carrying circular wire of radius R is placed in a magnetic field B perpendicular to its plane. The tension T along the circumference of the wire is

The moment of inertia of a uniform semicircular wire of mass 'M' and radius 'r' about a line perpendicular to the plane of the wire through the center is

A membrane is formed on a square wire frame of 10 cm side when taken out from a liquid of surface tension 20 xx 10^(-3)Nm^(-1) . Calculate the force acting on the surface of frame.

A square wire frame of L is dipped in a liquid, on taking out a membrane is formed. If the surface tension of liquid is T, force acting on the frame will be

A wire of resistance (3Omega) per meter is bent to from a regular hexagon of side 2 m. The resistance between points A and B as shown in figure is

Let a point P is lying inside a regular hexagon such that its perpendicular distances from the sides are 1,2,3,4,5,6 respectively.If the area of regular hexagon is A then the length of side of regular hexagon is-