`m[(-3,4)]+n[(4,-3)]=[(10,-11)]implies3m+7n=`

m["-3 4"]+n["4 -3"]=["10 -11"] find the value of 3m+7n .

-7m-[3n-{8m-(4n-10m)}] simplifies to 11m-5n( b) 11m-7n(c)11n-7m(d)13n-11m

Find (m+n)-:(m-n) , if : (i) m=(2)/(3) "and" n=(3)/(2) (ii) m=(3)/(4) "and" n=(4)/(3) (iii) m=(4)/(5) "and" n=-(3)/(10)

If sin A+cos A=m and sin^(3)A+cos^(3)A=n then (1)m^(3)-3m+n=0 (2) n^(3)-3n+ 2m=0(3)m^(3)-3m+2n=0 (4) m3+3m+2n=0

If (4m + 3n)/(4m - 3n) = (7)/(4) use properties of proportion to find : (i) m : n (ii) (2m^(2) - 11n^(2))/(2m^(2) + 11n^(2)) .

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m^3 + 3m + 2n = 0

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0