The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as
`x(m)=3t^(2)+4t+5`
Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The distance x covered by a body of 2 kg under the action of a force is related to time t as x=t^(2)//4 . What is the work done by this force in 2 seconds ?

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

The relation between the displaement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^3//3 , where x is in metre and t in second . Calculate the work done by the body in the first 2 seconds .

The relation between the displacement x and the time t for a body of mass 2 kg moving under the action of a force is geven by x=t^(3)//3 , where x is in metre and t in second ,Calculate the ork done by the body in first 2 seconds.

The displacement x of a body of mass 10 kg moving in one dimension under the action of a constant force is related to time by the equation t = sqrtx + 3 . Find the work done by the force in first 5 seconds.

A body of mass 6 kg is acted upon by a force which causes a displacement in it given by x = t^2/4 meter, where t is the time in second. The work done by the force in 2 seconds is

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is