The enthalpy of formation of `H_(2)O(l)` is `-285 KJ mol^(-1)` and enthalpy of neutralization of a stron acid and a strong bas is `-55 KJ mol^(-1)`. What is the enthalpy of formation of `OH^(-)` ions?

The enthalpy of formation of H_(2)O(l) is -280.70 kJ/mol and enthalpy of neutralisation of a strong acid and strong base is -56.70 kJ/mol. What is the enthalpy of formation of OH^(-) ions?

The enthalpy of formation of H_(2)O(l) is -280.70 kJ/mol and enthalpy of neutralisation of a strong acid and strong base is -56.70 kJ/mol. What is the enthalpy of formation of OH^(-) ions?

The enthalpy of formation of gaseous iodine is 62.5 kJ "mol"^(-1) . What is the enthalpy of sublimation of iodine at 25^(@)C ?

The enthalpy of the reaction : H_(2)O_(2)(l) rarr H_(2)O(l) + (1)/(2)O_(2)(g) is -98.3 KJ mol^(-1) and the enthalpy of formation of H_(2)O(l) is -285.6 kJ mol^(-1) . The enthalpy of formation of H_(2)O_(2)(l) is :

If the enthalpy of formation of H_2O(l) is -x kJmol and enthalpy of neutralization of HCl and NaOH is -y kJmol then enthalpy of formation of OH^(-) ion (in kJmol) is

If the enthalpy of formation of H_2O(l) is -x kj/mol and enthalpy of neutralization of HCl and NaOH is -y kj/mol then enthalpy of formation of OH^-1 ion (in kJ/mol) is

The enthalpy of the reaction : H_(2)O_(2)(l)toH_(2)O(l)+(1)/(2)O_(2)(g) is -23.5 kcal mol^(-1) and the enthalpy of formation of H_(2)O(l) is -68.3 kcal mol^(-1) . The enthalpy of formation of H_(2)O_(2)(l) is