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Enthalpy of neutralization of H(3)PO(3) ...

Enthalpy of neutralization of `H_(3)PO_(3) "with " NaOH " is" -106.68 "kJ"//"mol"`. If enthalpy of neutralization of HCL with NaOH is -55.84`"kJ"//"mole"`, then calculate enthalpy of ionization of `H_(3)PO_(3)` in to its ions in kJ.

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Enthalpy of neutralisation of H_(3)PO_(3) acid is -106.68kJ//mol using NaOH. If enthaly of neutralisation of HCl by NaOH is -55.84 kJ/mol. Calculate DeltaH_("ionization") " of " H_(3)PO_(3) into its ions

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