The function `f(x)=e^(-|x|)` is continuous everywhere but not differentiable at `x=0` continuous and differentiable everywhere not continuous at `x=0` none of these

The function f(x)=e^(|x|) is (a) Continuous everywhere but not differentiable at x=0 (b) Continuous and differentiable everywhere (c) Not continuous at x=0 (d) None of the above

The function f(x)=e^(|x|) is (a) Continuous everywhere but not differentiable at x = 0 (b) Continuous and differentiable everywhere (c) Not continuous at x = 0 (d) None of the above

The functionf(x)={(x(e^(1/x)-e^(-1/x)))/(e^(1/x)+e^(-1/x)), when x!=0 and f(x)=0 when x=0 (1) continuos everywhere but not differentiable at x=o (2) continuouas and differentiable everywhere (3) hot continuous at x=0 (4) differentiable at x=0

show that f(x) =|x| is continuous but not differentiable at x =0

The function f(x)=|x|+|x-1| is Continuous at x=1, but not differentiable at x=1 Both continuous and differentiable at x=1 Not continuous at x=1 Not differentiable at x=1

If f(x)={1/(1+e^((1,)/x)),x!=0 0,x=0,t h e nf(x) is continuous as well as differentiable at x=0 continuous but not differentiable at x=0 differentiable but not continuous at x=0 none of these

If f(x)={1/(1+e^((1,)/x)),x!=0 0,x=0,t h e nf(x) is continuous as well as differentiable at x=0 continuous but not differentiable at x=0 differentiable but not continuous at x=0 none of these

Leg f(x)=|x|,g(x)=sin xa n dh(x)=g(x)f(g(x)) then h(x) is continuous but not differentiable at x=0 h(x) is continuous and differentiable everywhere h(x) is continuous everywhere and differentiable only at x=0 all of these

If f(x)={1/(1+e^(1//x)),\ \ \ \ x!=0 0,\ \ \ \ \ \ \ \ \ \ \ x=0 , then f(x) is continuous as well as differentiable at x=0 (b) continuous but not differentiable at x=0 (c) differentiable but not continuous at x=0 (d) none of these

If f(x)={(1)/(1+e^(1/x)),quad x!=00,quad x=0 then f(x) is continuous as well as differentiable at x=0 (b) continuous but not differentiable at x=0 (c) differentiable but not continuous at x=0 (d) none of these