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Osmotic pressure of a solution obtained ...

Osmotic pressure of a solution obtained by mixing `100 mL` of 1.4% solution of urea (mol mass = 60) and `100 mL` of `3.42%` of cane sugar solution (mol mass = 342) at `20^(@)C (R = 0.0821 L atm K^(-1) mol^(-1))`

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A solution obtained by mixing 100 mL of 20% solution of urea (molar mass =60) and 100 mL of 1.6% solution of cane sugar (molar mass =342) at 300 K . (R=0.083 L bar K^(-1) mol^(-1) ). Calculate a.Osmotic pressure of urea solution b.Osmotic pressure of cane sugar solution c.Total osmotic pressure of solution

A solution obtained by mixing 100 mL of 20% solution of urea (molar mass =60) and 100 mL of 1.6% solution of cane sugar (molar mass =342) at 300 K . (R=0.083 L bar K^(-1) mol^(-1) ). Calculate a.Osmotic pressure of urea solution b.Osmotic pressure of cane sugar solution c.Total osmotic pressure of solution

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The osmotic pressure of a solution containing 100 ml of 3.4% solution (w/v) of urea (mol mass 60 g/mole) and 50 ml of 1.6% solution (w/v) of cane-sugar (mol mass 342 g/mole) at 27ºC is: