`y ^(2) + 2y - 3 =? `

Find the centre and radius of equation of circle in x^(2) + y^(2) - x + 2y - 3 = 0

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

Let's find the roots of the equations 3(y-5)^2 + 5y = (2y - 3)^2 - (y + 1)^2 + 1

Find the degree of the polynomials given below: 2 - y^2 - y^3+ 2y^8