A particle moving in a straight line has velocity-displacement equation as `v = 5 sqrt(1 + s).` Here v is in `ms^-1` and s in metres. Select the correct alternative.

A particle moving in a straight in a straight line has velocity and displacement equation as v = 4 sqrt(1 + s) , where v is in m/s and s is in m. The initial velocity of the particle is:

A particle is moving in a straight line . Select the correct option (s).

A particle moves in a straight line such that its displacement is s^(2)=t^(2)+1 Find. (i) velocity

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

For a particle moving along a straight line, its velocity 'v' and displacement 's' are related as v^(2) = cs , here c is a constant. If the displacement of the particle at t = 0 is zero, its velocity after 2 sec is:

Displacement time graph of a particle moving in a straight line is as shown in figure. Select the correct alternative (s) : .

Displacement time graph of a particle moving in a straight line is as shown in figure. Select the correct alternative (s) : .