The pressure at which equilibrium constant in terms of pressures is found to be equal to that in terms of mole fraction for the equilibrium,
` PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2) (g) `

Unit of equilibrium constant K_p for the reaction PCl_5(g) hArr PCl_3(g)+ Cl_2(g) is

1 mol PCl_(2)(g) is heated in a closed container of 2 litre capacity. If at equilibrium, the quantity of PCl_(5)(g) be 0.2 mol then calculate the value of equilibrium constant for the given reaction, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) .

Does the number of moles of reaction products increase, decrease of remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume? PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

Under certain conditions, the equilibrium constant for the decomposition of PCl_(5)(g) into PCl_(3)(g) and Cl_(2)(g) is 0.0211 "mol"L^(-1) . What are the equilibrium concentrations of PCl_(5),PCl_(3)d and Cl_(2) if the initial concentration of PCl_(5) was 1.00 M ?