A steel rod is 4000cm in diameter at `30^(@)C` A brass ring has an interior diameter of `3.992cm at 30^(@)` in order that the ring just slides onto the steel rod the common temperature of the two should be nearly `(alpha_(steel)=11xx10^(-6)/(^(@)C) and alpha_(brass)=19xx10^(-6)/(^(@)C)`

A steel rod is 3 cm in diameter at -10.00^@C . A brass ring has an interior diameter of 2.992 cm at -10.00^@C . At what common temperature will the ring just slide onto the rod ?

A steel rod is 3.000 cm at 25^@C . A brass ring has an interior diameter of 2.992 cm at 25^@C . At what common temperature will the ring just slide on to the rod?

A steel rod is 3.000 cm at 25^@C . A brass ring has an interior diameter of 2.992 cm at 25^@C . At what common temperature will the ring just slide on to the rod?

A steel rod is 3.000cm in diameter at 25^(@)C . A brass ring has an interior diameter of 2.9912cm at 25^(@)C . At what common temperature will the ring just slide onto the rod? alpha_("brass")=18xx10^(-6)K^(-1) and alpha_("steel")=12xx10^(-6)K^(-1)

A steel rod is 3.000 cm in diameter at 25^@C . A brass ring has an interior diameter of 2.992 cm at 25^@C . At what common temperature will the ring just slide onto the rod ? (Coefficient of linear expansion of steel= 12 xx 10^(-6) per k and coefficient of linear expansion of brass= 18 xx 10^(-6) per k) .

At 30^@C , the hole in a steel plate has diameter of 0.99970 cm. A cylinder of diameter exactly 1cm at 30^@C is to be slide into the hole. To what temperature the plate must be heated? (Given : alpha_(steel)=1.1xx10^-5//^@C )

At 30^(@) C, the hole in a steel plate has diameter of 0.99970 cm. A cylinder of diameter exactly 1 cm at 30^(@) C is to be slide into the hole. To what temperature the plate must be heated? (Given alpha_(Steel)=1.1xx10^(-5^(@))C^(-1)