`int x^3 ( 1- x^2 ) ^(5//2) dx`

int x(1+3x^2)^(5/2) dx

int (1-x^2 - 3x^5) dx

Evaluate: (i) int(5x^(2) + 2x^(-5) - 7x + 1/(sqrt(x)) +5/x) dx (ii) int(3sinx - 4 cosx + 5 sec^(2) x - 2cosec^(2)x) dx (iii) int(1-x)(2+3x)(5-4x)dx (iv) int((3x^(4) - 5x^(3) + 4x^(2) -x + 2)/(x^(3)))dx , (v) int(x^(2) + 1/(x^(2)))^(3) dx

int x ^ (5) (1 + 2x ^ (3)) ^ ((5) / (3)) dx

Evaluate each of the following integrals: int x^(4)dx( ii) int x^(5/4)dx (iii) int(1)/(x^(5))dx( iv )int(1)/(x^(3)/2)dx

int x^(5)(1+x^(3))^((2)/(3))dx

int _ (- 1) ^ (1) (2x + 3) / (5x + 2) dx

The value of int_0^1 4x^3 {d^2/(dx^2) (1 - x^2)^5 } dx is

int _(-2) ^(3) (1)/(x +5) dx =