मान ज्ञात कीजिए |
`abs((sinx,-cosx),(cosx,sinx))`

int(cosx)/(cosx-sinx)dx=

y=(sinx)^(cosx)+(cosx)^(sinx)

int (sinx-cosx)/(cosx+sinx)dx =

((sinx - cosx)/(sinx + cosx))

int (2sinx-cosx)/(2cosx+sinx)dx =

int(dx)/((sinx+cosx)(2cosx+sinx))=

Solve (sinx)/(1+cosx)+(1+cosx)/(sinx)

If -pi/4lexlepi/4 then abs((sinx,cosx,cosx),(cosx,sinx,cosx),(cosx,cosx,sinx))=0 then find the number of solution

The number of distinct roots of abs((sinx, cosx, cosx),(cosx, sinx, cosx),(cosx, cosx, sinx))=0 in the interval -pi/4 le x le pi/4 is