A particle moves in xy plane. The rate of changes of `theta` at time t=2 second ( where `theta` is the angle which its velocity vector maks with positive x-axis) is

A particle moves in xy-plane. The position vector of particle at any time is vecr={(2t)hati+(2t^(2))hatj}m. The rate of change of theta at time t = 2 second. ( where 0 is the angle which its velocity vector makes with positive x-axis) is :

A particle moves in xy-plane. The position vector of particle at any time is vecr={(2t)hati+(2t^(2))hatj}m. The rate of change of 0 at time t = 2 second. ( where 0 is the angle which its velocity vector makes with positive x-axis) is :

A particle moves in a plane such that its coordinates changes with time as x = at and y = bt , where a and b are constants. Find the position vector of the particle and its direction at any time t.

A particle moves in a plane such that its coordinates changes with time as x = at and y = bt , where a and b are constants. Find the position vector of the particle and its direction at any time t.

If a particle moves in a circle, describing equal angles in aqual intervals of time in a plane about a fixed point, its velocity vector