The periodic time (T) of a simple pendulum of length (L) is given by `T=2pisqrt((L)/(g))`. What is the dimensional formula of `Tsqrt((g)/(L))`?

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

Time period T of a simple pendulum of length l is given by T=2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

Time period T of a simple pendulum of length l is given by T = 2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

What are the variables in the formula T=2pisqrt((l)/(g)) ?