Oxygen is prepared by catalytic decomposition of potassium chlorine `(KClO_(3))`. Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen `(O_(2))`. How many moles and how many grams of `KClO_(3)` are required to produce 2.4 mole `O_(2)`?

Oxygen is prepared by the catalytic decomposition of potassium chlorate ( KClO_(3) ). Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen ( O_(2) ). If 2.4 mol of oxygen is needed for an experiment, how many grams of potassium chlorate must be decomposed ?

Write the catalyst used in the decomposition of potassium chlorate to get potassium chloride and oxygen.

Name the catalyst used in the preparation of oxygen from KClO_(3) or decomposition of potassium chlorate.

What mass of potassium chlorate ( KClO_3 ) on heating gives 1.491 g of potassium chloride (KCl) and 0.672 litres of oxygen at NTP?

What mass of potassium chlorate (KClO_3) on heating gives 1.591 g of potassium chloride (KCl) and 0.672 litres of oxygen at NTP?

What mass of potassium chlorate ( KClO_3 ) on heating gives 1.951 g of potassium chloride (KCl) and 0.672 litres of oxygen at NTP?