An electron and proton are accelerated through same potential, then `lamda_e // lamda_p` will be

An electron (mass m_e ) and a proton (mass m_p ) are accelerated through the same potential, then lambda_e//lambda_p =

An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be

An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be

An electron and a proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths will be

The ratio of wavelength of deutron and proton accelerated through the same potential difference will be -

A proton and an electron are accelerated by the same potential difference, let lambda_(e) and lambda_(p) denote the de-Broglie wavelengths of the electron and the proton respectively

A proton and an electron are accelerated by the same potential difference, let lambda_(e) and lambda_(p) denote the de-Broglie wavelengths of the electron and the proton respectively

A proton and an electron are accelerated by the same potential difference, let lambda_(e) and lambda_(p) denote the de-Broglie wavelengths of the electron and the proton respectively

A proton of mass m_p and electron of mass m_e are accelerated through the same potential the ratio of debroglie wavelength of electron to that of proton is

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is