There is ice formation on a tank of water of thickness 10 cm.How much time it will take to have a layer of 0.1 cm below it ?The outer temperature is `-5^(@)C`, the thermal conductivity of ice is ` 0.005 calcm^(-1)``""^(@)C^(-1)` and latent heat of ice is `80cal//g` and the density of ice is `0.91 gcm^(-3)`:

The thickness of ice in a lake is 10 cm and its temperature is -10^(0)C . The thermal conductivity of ice = 0.004 cal cm^(-1)" sec"^(-1)""^(0)C^(-1) . Density of ice = 0.92 g/cc, latent heat of ice = 80 cal/g. The time taken for thickness of ice to be doubled is

Calculate the rate of increment of the thickness of ice layer on a lake when thickness of ice is 10 cm and the air temperature is -5^(@) C . If thermal conductivity of ice is 0.008 cal "cm"^(-1) "s"^(-1)°"C"^(-1) , density of ice is 0.91 xx 10^(3) "kg m"^(-3) and latent heat is 79.8 cal "gm"^(-1) . How long will it take the layer to become 10.1 cm ?

An ice layer of thickness 3 cm is formed on a lake. How much time will it take to increase the thickness of ice by 2 mm if temperature of air is -30^@C ? Take, Density of ice = 1 g cm^(-3) , Latent heat of ice = 80 cal g^(-1) , Conductivity of ice = 0.008 cal s^(-1) cm^(-1) ""^@C^(-1)

Time in which a layer of ice of thickness 10 cm will increase by 5 cm on te surface of a pond when temperature of the surrounding is -10^(@)C coefficient of thermal conductivity of ice K=0.005((Cal)/(cm-sec-.^(@)C)) and density rho=0.9gram//cm^(3) (L=80cal/g)

Time in which a layer of ice of thickness 10 cm will increase by 5 cm on te surface of a pond when temperature of the surrounding is -10^(@)C coefficient of thermal conductivity of ice K=0.005((Cal)/(cm-sec-.^(@)C)) and density rho=0.9gram//cm^(3) (L=80cal/g)

10g of water at 30^(@)C and 5g of ice at -20^(@) C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice= 0.5 cal g^(-1) (""^(0)C)^(-1) and latent heat of fusion of ice =80 cal g^(-1)

A layer of ice 29 cm thick has formed on a pond. The temperature of air is -10^(@)C . Find how long will it take for another 0.1 cm layer of water to freeze? Conductivity of ice = 2.1 J s^(-1)m^(-1)K^(-1) . Latent heat capacity of ice =3.36 xx 10^(5) J kg^(-1) and density of ice = 1000 kg m^(-3) .

A lake surface is exposed to an atmosphere where the temperature is lt 0^(@)C . If the thickness of the ice layer formed on the surface grows form 2cm to 4cm in 1 hour. The atmospheric temperature, T_(a) will be- (Thermal conductivity of ice K = 4 xx 10^(-3) cal//cm//s//.^(@)C , density of ice = 0.9 gm//ice. Latent heat of fustion of ice = 80 cal//m . Neglect the change of density during the state change. Assume that the water below the ice has 0^(@) temperature every where)

A lake surface is exposed to an atmosphere where the temperature is lt 0^(@)C . If the thickness of the ice layer formed on the surface grows form 2cm to 4cm in 1 hour. The atmospheric temperature, T_(a) will be- (Thermal conductivity of ice K = 4 xx 10^(-3) cal//cm//s//.^(@)C , density of ice = 0.9 gm//ice. Latent heat of fustion of ice = 80 cal//m . Neglect the change of density during the state change. Assume that the water below the ice has 0^(@) temperature every where)