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Parallelogram ABCD and rectangle ABEF a...

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equalareas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

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Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram ABCD and rectangle ABEF are on the base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram A B C D and rectangle A B E F have the same base A B and also have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram A B C D and rectangle A B E F have the same base A B and also have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle. GIVEN : A ||^(gm)A B C D and a rectangle A B E F with the same base A B and equal areas. TO PROVE : Perimeter of ||^(gm)A B C D > Perimeter of rectangle ABEF i.e. A B+B C+C D+A D > A B+B E+E F+A F

Parallelogram A B C D and rectangle A B E F have the same base A B and also have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle. GIVE : A ^(gm)A B C D and a rectangle A B E F with the same base A B and equal areas. TO PROVE : Perimeter of ^(gm)A B C D > P e r i m e t e rofr e c t a nge l ABEF i.e. A B+B C+C D+A D > A B+B E+E F+A F

In Fig. if parallelogram ABCD and rectangle ABEF are of equal area, then :