For the reaction
`C_(2)H_(4(g))+3O_(2(g)) rarr 2CO_(2(g))+2H_(2)O_((l))` the difference between enthalpy change and internal energy change is

The combustion of methane is written as CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l) The difference between enthalpy change and energy change is equal to:

For the reaction C_(2)H_(4)(g)+3O_(2)(g) rarr 2CO_(2) (g) +2H_(2)O(l) , Delta E=-1415 kJ . The DeltaH at 27^(@)C is

The value of enthalpy change (Delta H) for the reaction : C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 2CO_(2)(g) + 3H_(2)O(l) at 27^(@)C is - 1366.5 kJ mol^(-1) . The value of internal energy change for the above reaction at the temperature will be :

The value of enthalpy change (DeltaH) for the reaction C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l) at 27^(@)C is -1366.5KJmol^(-1) . The value of internal energy change for the above reaction at this tempearature will be

The value of enthalpy change (DeltaH) for the reaction C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l) at 27^(@)C is -1366.5 kJ mol^(-1) . The value of internal energy change for the above reactio at this temperature will be