फलन`f(x)` जिसके लिए
` f(x) {: {(x^(2),x !=1),(2,x=1):}`
दिखाइए कि ` lim _( x to 1) f( x) = 1 `

The function f(x), for which f(x)={x^(2),xne1 2, x=1} Show that: lim_(x to 1) f(x)=1

The function f(x), for which f(x)={x^(2),xne1 2, x=1} Show that: lim_(x to 1) f(x)=1

If f(x)={:{(2x+1,x le 0),(3(x+1),x gt 0):} . Find lim_(x to 0) f(x) and lim_(x to 1) f(x) .

Find lim_(x to 1) f(x) if f(x)={:{(x^2-1,x le1),(x^2+1, x gt1):}

For the function f(x) = 2 . Find lim_(x to 1) f(x)

For the function f(x) = 2 . Find lim_(x to 1) f(x)

If (x^2+x−2)/(x+3) 1) f(x) then find the value of lim_(x->1) f(x)

If a differentiable function f(x) satisfies lim_(x to -1) (f(x) +1)/(x^(2)-1)=(3)/(2) Then what is lim_(x to -1) f(x) equal to ?