The torque needed to produce an angular acceleration of 18rad/`"sec"^2` in a body of moment of inertia 2.5kg-`m^2` would be -

A torque of 2.0xx10^(-4)Nm is applied to produce an angular acceleration of 4"rad"s^(-2) in a rotating body. What is the moment of inertia of the body?

A torque of 2.0 xx 10^(-4) Nm is applied to produce an angular acceleration of 4 "rad s"^(-2) in a rotating body. What is the moment of inertia of the body ?

A torque of magnitude 2000 Nm acting on a body produces an angular acceleration of 20" rad/s"^(2) , The moment of inertia of the body is

The torque acting is 2000 Nm with an angular acceleration of 2rad//s^(2) . The moment of inertia of body is

A torque of 2 newton-m produces an angular acceleration of 2 rad//sec^(2) a body. If its radius of gyration is 2m, its mass will be:

A torque of 2 newton-m produces an angular acceleration of 2 rad//sec^(2) a body. If its radius of gyration is 2m, its mass will be:

If a torque of magnitude 100 Nm acting on a rigid body produces an angular acceleration of 2 rad//s^(2) , then the moment of inertia of that body will be

In a ring of mass 0.5 kg and radius sqrt(5) m, to produce angular acceleration of 18rad//s^(2) in this body, applied torque (in N-m) should be