The angular velocity of a body is `vec(omega)=2hati+3hatj+4hatk` and a torque `vec(tau)=hati+2hatj+3hatk` acts on it. The rotational power will be

The angular velocity of a body is given by vec(omega)=3hati+2hatj+3hatk A torque vec(tau)=2hati+3hatj+4hatk acts on it. Then the rotational power will be

The angular velocity of a body is vecomega=3hati+5hatj+6hatk("radian"//s) . A torque vectau=hati+2hatj+3hatk(Nm) acts on it. The rotational power (in watt) is

The angular velocity of a body is vecomega=3hati+5hatj+6hatk("radian"//s) . A torque vectau=hati+2hatj+3hatk(Nm) acts on it. The rotational power (in watt) is

Find |vec(a)xx vec(b)| , if vec(a)=hati-7hatj+7hatk and vec(b)=3hati-2hatj+2hatk .

The projection of the vector vec alpha=2hati+3hatj+2hatk on the vector vec beta=hati+2hatj+hatk is -