A body starts with a velocity `(2hati+3hatj+11hatk)m//s` and moves with an acceleration `(5hati+5hatj-5hatk)m//s^(2)`. What is its velocity after `0.2 sec`?

A body starts with a velocity 2 hati +3hatj +11 hatk m/s and moves with an acceleration 10 hati +10 hatj +10 hatk m//s^2 . What is its velocity after 0.2 seconds ?

A body starts with a velocity 2 hati +3hatj +11 hatk m/s and moves with an acceleration 10 hati +10 hatj +10 hatk m//s^2 . What is its velocity after 0.2 seconds ?

A body starts with a velocity (2hat i+3hatj+11k) m/s with an acceleration (5hati+5hatj-5k)ms//s^(2) .What is its velocity after 0.2 sec?

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

If the velocity is vecv=2hati+t^(2)hatj-9hatk then the magntidue of acceleration at t=0.5s is

The initial velocity of an object is vecu = 5hati + 10hatj m//s . Its constant acceleration is veca = 2hati+ 3 hatj m//s^2 . Determine the velocity and the displacement after 5 s.