Assertion : When certain wavelength of light fall on metal surface it ejects electron.
Reason : Light was wave nature.

In photoelectric experiment when wavelength of light is 642.4 nm falls on metal surface stopping potential of photo electron is 0.48eV. What will be the stoppingpotential when wavelength of light used is 474 nm?

If I_(0) is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given by

If lambda_(0) is the threshold wavelength for photoelectric emission. lambda wavelength of light falling on the surface on the surface of metal, and m mass of electron. Then de Broglie wavelength of emitted electron is :-

If lambda_(0) is the threshold wavelength for photoelectric emission. lambda wavelength of light falling on the surface on the surface of metal, and m mass of electron. Then de Broglie wavelength of emitted electron is :-

Assertion : The number of electrons ejected from a metal surface depend upon the frequency of light. Reason : There is a time lag between the striking of light beam and the ejection of electrons from the metal surface.

Assertion : The number of electrons ejected from a metal surface depend upon the frequency of light. Reason : There is a time lag between the striking of light beam and the ejection of electrons from the metal surface.

When a light of suitable frequency strikes a metal surface, then the number of ejected electrons :