A proton moving withh a velocity `2.5xx10^(7)m//s` enters a magnetic field of intensity `2.5T` making an angle `30^(@)` with the magnetic field. The force on the proton is

A proton moving with a velocity 2 . 5 xx 10^(7) m-s ^(-1) , enters a magnetic field of intensity 2.5 T at an angle 30^(@) with the magnetic field. The force on the proton is

A proton moving with a velocity of 2.5 xx 10^(7) m/s , enter a magnetic feildof 2T, making an angle of 30◦ with the magnetic field. The force acting on the proton

A proton with a speed of 2xx10^(7)m.s^(-1) enters a magnetic field of flux density 1.5Wb.m^(-2) , making an angle of 30^(@) with the field. The force acting on the proton is

A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)

A proton with a speed of 2xx10^7 m.s-1 enters a magnetic field of flux density 1.5 Wb.m^-2 , making an angle of 30^@ with the field. The force acting on the proton is

A proton moving with velocity (10^7) m/s to enters a magnetic field of 1.5 T making an angle 30° with the direction of the field. Find the radius of the helical path and its frequency of rotational motion

A beam of protons moving with a velocity of 4 xx 10^(5) m/s enters a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam? [m_p=1.67 xx 10^(-27) kg and the charge on the proton =1.6 xx 10^(-19) C]

An electron moving with a velocity of 4.5 xx 10^(7)m/s enters a magnetic field of 2.5 T at an angle of 30^(o) calculate the force on the electron.

A proton moving with a velocity 3xx10^(5)m//s enters a magnetic field of 0.3 tesla at angle of 30^@ with the field. The radius of curvature of its path will be (e/m for proton =10^(8)C//kg )