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1 mole each of CO(g), H(2)O(g), H(2)(g) ...

1 mole each of `CO(g), H_(2)O(g), H_(2)(g)` and `CO_(2)(g)` are placed in one placed in one litre flask at `25^(@)C`. When following equilibrium is set -up `CO(g)+H_(2)O(g)hArr CO_(2)(g)+H_(2)(g)`
`K_(p)=0`. Hence `CO_(2)` present at equilibrium is `:`

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