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The height of a ball thrown into the air...

The height of a ball thrown into the air with an initial vertical velocity of 24 fts from a height of 6 feet above the ground is given by the equation: `h = 16t^2 + 24 t +6`, where t is the time in seconds, for the ball has been in air. After how many seconds is the ball at a height of 14 feets

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