Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take `g = 10 m//s^2.`

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2))

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2)) 1 s 2 s 3 s 4 s

Two particles are released from the same height at an interval of 1s . How long aftger the first particle begins to fall will the two particles be 10m apart? ( g=10m//s^(2) )

Two particles are released from the same height at an interval of 1s . How long aftger the first particle begins to fall will the two particles be 10m apart? ( g=10m//s^(2) )

Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Two bodies begin to fall freely from the same height. The second one begins to fall tau s after the first. The time after which the 2st body begins to fall, the distance between the bodies equals to l is

two particals are thrown vertically upward with the same initial velocity of 50 m//s but 2 s apart. How long after the first one thrown, will they meet?

Two balls are released from the same height at an interval of 2s. When will the separation between the balls be 20m after the first ball is released? Take g=10m//s^(2) .