The lattice enthalpy of solid `NaCl` is `772 kJ mol^(-1)` and enthalpy of solution is `2 kJmol^(-1)`. If the hydration enthaply of `Na^(+)` & `Cl^(-)` ions are in the ratio of `3 : 2.5`, what is the enthalpy of hydration of chloride ion ?

The lattice enthalpy of solid NaCI is 772 kJ mol^(-1) and enthalpy of solution is 2kJ mol^(-1) . If the hydration enthalpy of Na^(+) &CI^(-) ions are in the ratio of 3: 25, what is the magnitude of enthalpy of hydration (in kJ) of chloride ion ?

The lattice energy of solid KCl is 181 kcal mol^(-1) and the enthalpy of solution of KCl in H_(2)O is 1.0 kcal mol^(-1) . If the hydration enthalpies of K^(o+) and Cl^(Theta) ions are in the ratio of 2:1 then the enthalpy of hydration of K^(o+) is -20xK cal mol^(-1) . Find the value of x .

The lattice energy of solid KCI is 181 kcal mol^(-1) and the enthalpy of solution of KCI in H_(2)O is 1.0 kcal mol^(-1) . If the hydration enthalpies of K^(o+) and CI^(Theta) ions are in the ratio of 2:1 then the enthalpy of hydration of K^(o+) is -20xK cal mol^(-1) . Find the value of x .

The lattice energy of solid NaCI is 180 kcal mol^(-1) . The dissolution of the solid in H_(2)O is endothermic to the extent of 1.0 kcal mol^(-1) . If the hydration energies of Na^(o+) and CI^(Theta) ions are in the ratio of 6:5 what is the enthalpy of hydration of sodium ion?

The lattice energy of solid NaCI is 180 kcal mol^(-1) . The dissolution of the solid in H_(2)O is endothermic to the extent of 1.0 kcal mol^(-1) . If the hydration energies of Na^(o+) and CI^(Theta) ions are in the ratio of 6:5 what is the enthalpy of hydration of sodium ion?

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .