Statement– 1 : In the given fig. `"a"=(("m"_(2)-"m"_(1))/("m"_(1)+"m"_(2)))"g"`
Statement– 2 : In the given fig., `"T"=("m"_(1)+"m"_(2))/(2"m"_(1)"m"_(2))`

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations : ( i ) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( ii ) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( iii ) When m_(1)=m_(2)=m . In this case a=0 , T=mg If m_(1)=10kg , m_(2)=6kg and g=10m//s^(2) then what is the acceleration of masses ?

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations : ( i ) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( ii ) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( iii ) When m_(1)=m_(2)=m . In this case a=0 , T=mg If m_(1)=10kg , m_(2)=6kg and g=10m//s^(2) What is the tension in the string ?

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations : ( i ) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( ii ) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g ( iii ) When m_(1)=m_(2)=m . In this case a=0 , T=mg If m_(1)=10kg , m_(2)=6kg and g=10m//s^(2) If the pulley is pulled upward with acceleration equal to the acceleration due to gravity, what will be the tension in the string

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations: (i) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (ii) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (iii) When m_(1)=m_(2)=m . In this case a = 0, T = mg What is the tension in the string?

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations: (i) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (ii) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (iii) When m_(1)=m_(2)=m . In this case a = 0, T = mg If m_(1)=10kg, m_(2)=6kg and g =10m//s^(2) then what is the acceleration of masses?

In the fig, find the acceleration of m_(1) and m_(2)

In the fig, find the acceleration of m_(1) and m_(2) .

If m-(1)/(m)=5 then find m^(2)-(1)/(m^(2))