A particle rotates in U.C.M with tengential velocity 'v' along a ghorizontal circle of diameter 'D' . Total angular displacement of the particle in time 't' is

A particle performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t is

A particle is performing circular motion with its diameter d and velocity v. Then the angular displacement of the particle in time t is

The tangential velocity of a particle making p rotations along a circle of radius pi in t seconds is

The tangential velocity of a particle making p rotations along a circle of radius pi in t seconds is

A particle is moving along a horizontal circle with a speed V = at - bt^(3) . Then angular displacement of particle at any instant is (consider at t=0 , theta_(0) = 0 and 'r' is radius of circle and theta is angular displacement at any instant)

A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :