`(9m+7)/(2)-(m-(m-4)/(7))=27` then find `m`

"21m^(2)-:7m

If (7)/(m-sqrt(3))=(sqrt(3))/(m)+(4)/(2m) , what is the value of m ?

Solve : (9m+4)/(5) - (27 m + 1)/(8) - (1)/(2) = 0

If = log "" ( 5)/(7) , m = log ""( 7)/(9) and n = 2 ( log 3 - log sqrt5) , find the value of 7^(l+ m + n )

Solve: (18 - 2m)/(5) + (4m + 3)/(7) ge (m)/(5) + (8)/(7)

If (7m+2n)/(7m-2n)=5/(3) use properties of proportion to find (i) m:n (ii) (m^(2)+n^(2))/(m^(2)-n^(2))