If `x^2+y^2=4`and `u^2+v^2=9` where `x,y,u` and `v` are real numbers then find the maximum value of `(xu-yv)`

If u and v are real numbers and (u+3)^(2)+(v+5)^(2)=0 , then find the values of u and v.

Suppose x and y are real numbers and that x^(2)+9y^(2)-4x+6y+4=0. Then the maximum value of ((4x-9y))/(2) is

int_(1)^(2)((x^(2)-1)dx)/(x^(3).sqrt(2x^(4)-2x^(2)+1))=(u)/(v) where u and v are in their lowest form. Find the value of ((1000)u)/(v) .

int_(1)^(2)((x^(2)-1)dx)/(x^(3).sqrt(2x^(4)-2x^(2)+1))=(u)/(v) where u and v are in their lowest form. Find the value of ((1000)u)/(v) .

int_(1)^(2)((x^(2)-1)dx)/(x^(3)*sqrt(2x^(4)-2x^(2)+1))=(u)/(v) where u are ( in their blowest form.Find the value of )/(sqrt(2x^(4)-2x^(2)+1))=(u)/(v) where of ((1000)u)/(v)

If 4x^(4)+9y^(4)=64 then the maximum value of x^(2)+y^(2) is (where x and y are real)

If u=sin^(-1)((2x)/(1+x^2)) and v=tan^(-1)((2x)/(1-x^2)) , where -1

If w = u^(2)e ^(v) where u = x/y, v = y log x find (delw)/(delx)

v^2 = u^2+2as , where v and u are velocities, ‘a’ acceleration and ‘s’ displacement.Write the dimensions of the following: v^2 = ? U^2= ? 2as = ?

If x = 2, y = 3, u = - 2 and v = - 3, in which quadrant does the point (x + y, u + v) lie ?