If the midpoint of the chord of the ellipse `x^2/16+y^2/25=1`is `(0,3)`

If the mid-point of a chord of the ellipse (x^2)/(16)+(y^2)/(25)=1 (0, 3), then length of the chord is (1) (32)/5 (2) 16 (3) 4/5 12 (4) 32

If the mid-point of a chord of the ellipse (x^2)/(16)+(y^2)/(25)=1 (0, 3), then length of the chord is (1) (32)/5 (2) 16 (3) 4/5 12 (4) 32

If the mid-point of a chord of the ellipse (x^2)/(16)+(y^2)/(25)=1 (0, 3), then length of the chord is (1) (32)/5 (2) 16 (3) 4/5 (4)12 (5) 32

If the mid-point of a chord of the ellipse (x^(2))/(16)+(y^(2))/(25)=1(0,3), then length of the chord is (32)/(5)(2)16(3)(4)/(5)12(5)32

Find the foci of the ellipse x^2/25+y^2/16=1

The midpoint of the chord 4x+5y-13=0 of the ellipse 2x^(2)+5y^(2)=20 is

The midpoint of a chord of the ellipse x^(2)+4y^(2)-2x+20y=0 is (2, -4). The equation of the chord is

The locus of the middle point of chords of an ellipse (x^(2))/(16)+(y^(2))/(25)=1 passing through P(0,5) in another ellipse E.The coordinates of the foci of the ellipse E,is