The equation of circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length `3a` is `x^2+y^2=a^2` `x^2+y^2=4a^2` `x^2+y^2=16 a^2` `x^2+y^2=9a^2`

The equation of circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=a^(2)x^(2)+y^(2)=4a^(2)x^(2)+y^(2)=16a^(2)x^(2)+y^(2)=9a^(2)

The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is: a x^(2)+y^(2)=9a^(2) b) x^(2)+y^(2)=16a^(2) c) x^(2)+y^(2)=4a^(2) d) x^(2)+y^(2)=a^(2)

Show that the equation of the circle with centre at origin and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=4a^(2) .

Show that the equation of the circle with centre at origin and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=4a^(2) .

Find the equation of the circle passing through the vertices of the triangle whose sides are : x+y =2, 3x-4y =6 and x-y=0.

Find the equation of the circle passing through the vertices of the triangle whose sides are : x-y=0, 3x+ 2y = 5 and x + 2y=5.

Equation of the circle with centre at (1,-2) , and passing through the centre of the circle x^(2) + y^(2) + 2y - 3 = 0 , is

Find the equation of the circle passing through the vertices of the triangle whose sides are : x - y = 0 , 3x + 2y = 5 and x + 2y = 5 .

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is

Find the equation of the circle whose centre is the point (1,-2) and which passes through the centre of the circle x^2 + y^2 + 2y = 3 .