`int(x^2)/(x^4+5x^2+6)dx=`

int(x^(2))/(x^(2)-5x+6)dx=

Compute the following integrals: int(x^2+4x)/(x^3+6x^2+5)dx

int(x+1)/(x^2+5x+6)dx=

int (x^3+5x^2+4)/x^2 dx=

Evaluate the following integrals. int(4x-9)/(x^2-5x+6)dx

If int(x+2)/(2x^(2)+6x+5)dx =P int(4x+6)/(2x^(2)+6x+5)dx+(1)/(2) int (dx)/(2x^(2)+6x+5') Then the value of P is

4) int(x^(2)+1)/(x^(2)-5x+6)dx

int(5x^2)/((x+1)(x^2+4))dx=

int(x+2)/(2x^(2)+6x+5)*dx

int(x^(2)+5x+5)/(x^(4))dx