At `600^(@)C,K_(P)` for the following reaction is 1 atm.
`X(g) rarr Y(g) + Z(g)`
At equilibrium, 50% of X (g) is dissociated. The total pressure of the equilibrium system is p atm. What is the partial pressure (in atm) of at equilibrium ?

At 600^(@)C,K_(P) for the following reaction is 1 atm. X(g) rarr Y(g) + Z(g) At equilibrium, 50% of X (g) is dissociated. The total pressure of the equilibrium system is p atm. What is the partial pressure (in atm) of gases at equilibrium ?

C(s)+CO_(2)(g) iff 2CO(g) . At equilibrium, 25% of the CO_(2) got converted into CO. If the equilibrium pressure is 12 atm, the partial pressure of CO_(2) at equilibrium is

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For the reaction C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63 atm at 100 K. If at equilibrium p_(CO)=10p_(CO_(2)) then the total pressure of the gases at equilibrium is

For the reaction C(s) +CO_(2)(g) rarr 2CO(g) , k_(p)=63 atm at 100 K. If at equilibrium p_(CO)=10p_(CO_(2)) then the total pressure of the gases at equilibrium is

For the reaction C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63 atm at 100 K. If at equilibrium p_(CO)=10p_(CO_(2)) then the total pressure of the gases at equilibrium is

In the reaction 2 SO_(3 (g)) , hArr 2 SO_(2 (g)) + O_(2 (g)) , SO_(3 (g)) is 50 % dissociated at 27^(@)C when the equilibrium pressure is 0.5 atm . Partial pressure of SO_(3 (g)) at Equilibrium is

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