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At 500 kbar pressure density of diamond...

At 500 kbar pressure density of diamond and graphite are `3 "g"//"cc" and 2 "g"//"cc"` respectively, at certain temperature T. Find the value of |DeltaH-DeltaU|`("in kJ"//"mole")`for the conversion of 1 mole of graphite 1 mole of diamond at 500 kbar pressure.
(Given : `1 "bar" = 10^(5) "N"//"m"^(2))`

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