Two vector `vec(A)` and `vec(B)` have equal magnitudes. Then the vector `vec(A) + vec(B)` is perpendicular :

The vectors vec(a) and vec(b) are perpendicular if :

Two vectors vec(A) and vec(B) have equal magnitudes . If magnitude of vec(A) + vec(B) is equal to n times the magnitude of vec(A) - vec(B) , then the angle between vec(A) and vec(B) is

Two vectors vec(A) and vec(B) have precisely equal magnitudes. For the magnitude of vec(A) + vec(B) to be larger than the magnitude of vec(A)-vec(B) by a factor of n , what must be the angle between them?

Two vector vec(A)andvec(B) have equal magnitudes. If magnitude of vec(A)+vec(B) is equal to n time the magnitude of vec(A)-vec(B) , then angle to between vec(A) and vec(B) is

Two vectors vec A and vec B have equal magnitudes.The magnitude of (vec A+vec B) is 'n' times the magnitude of (vec A-vec B).The angle between vec A and vec B is:

Two vector vec(V)andvec(V) have equal magnitudes. If magnitude of vec(A)+vec(B) is equal to n time the magnitude of vec(A)-vec(B) , then angel to between vec(A) and vec(B) is

Two vectors vec A and vec B have equal magnitudes.If magnitude of (vec A+vec B) is equal to n xx of the magnitude of (vec A-vec B) then the angle between vec A and vec B is :

Two vectors vec A and vec B have equal magnitudes. If magnitude of vec A-vec B is equal to (n) times the magnitude of vec A-vec B , then angle between vec A and vec B is ?

The resultant and dot product of two vectors vec(a) and vec(b) is equal to the magnitude of vec(a) . Show that when the vector vec(a) is doubled , the new resultant is perpendicular to vec(b) .

Two vectors vec(A) and vec(B) have magnitudes 2 and 2sqrt(2) respectively. It is found that vec(A).vec(B) = |vec(A) xx vec(B)| , then the value of |(vec(A)+vec(B))/(vec(A)-vec(B))| will be :