A particle originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance `h` below the highest points, such that `h` is equal to

A partical originally at rest at the highest point of a smooth vertical circle is slightly displaced. It will leave the circle at a vertical distance h below the highest points, such that h is equal to

Find the expression for velocity at highest point in a vertical circle.

In figure, a particle is placed at the highest point A of a smooth sphere of radius r. It is given slight push, and it leaves the sphere at B, at a depth h vertically below A. The value of h is

In figure, a particle is placed at the highest point A of a smooth sphere of radius r. It is given slight push, and it leaves the sphere at B, at a depth h vertically below A. The value of h is

In a vertical circle the minimum or critical velocity at highest point of path will be

Particle slides down the surface of a smooth fixed sphere of radius r starting from rest at the highest point. Find where it will leave the sphere. Show that it strike the horizontal plane through the lowest point of the sphere at a distance equal to 5[sqrt(5)+4sqrt(2)](r//27) from the vertical diameter.

A particle is projected along the inner surface of a smooth vertical circle of radius R , its velocity at the lowest point being (1//5)(sqrt(95 gR)) . If the particle leaves the circle at an angular distance cos^(-1)(x//5) from the highest point, the value of x is.