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If Delta=|(sqrt6,2i,3+sqrt6),(sqrt12,sqr...

If `Delta=|(sqrt6,2i,3+sqrt6),(sqrt12,sqrt3+sqrt8i,3sqrt2+sqrt6i),(sqrt18,sqrt2+sqrt12i,sqrt27+2i)|` then `Delta` is `(i^2=-1)`

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If Delta=|(sqrt(6),2i,3+sqrt(6)),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i)| then Delta is a)an integer b)a rational number c)an irrational number d)an imaginary number

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

(sqrt(3)-i sqrt(2))/(2sqrt(3)-i sqrt(2))

(-sqrt3 + sqrt(-2))(2sqrt3-i)

sqrt(i)+sqrt(-i)=sqrt(2)

sqrt(i)-sqrt(-i)=sqrt(2)