A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is `27^@C`. (Melting point of lead=`327^@C`, specific heat of lead =`0.03 calories //gm//^@C`, latent jeat of fusion of lead=`6calories//gm,J=4.2 joules //calorie`).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead= 327^@C , specific heat of lead = 0.03 cal //gm-^@C , latent heat of fusion of lead= 6 cal//gm,J=4.2 J //cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g.^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g-^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25% of heat is absrobed by the obstacle find the velocity of the bullet if the initial temperature was 27^(@)C. Melting point of lead = 327^(@)C, specific heat of lead =0.03 cal g ^(-1) ""^(@)C ^(-1). Latent heat of fusion of lead =6 cal g ^(-1).

A bullet of lead melts when stopped by obstacle. Assuming that 25 per cent of the heat is absorbed by the osbtacle, find the velocity of the bullet if its initial temperature is 27^(@)C . (Melting point of lead 327^(@)C , specific heat capacity of lead =30 cal kg^(-1)K^(-1) specific latent heat of fusion of lead =6000 cal kg^(-1) and J=4.2 joules cal^(-1) )

During the Indo-Pakistan war, a soldier observed that the lead bullet fired by him just melted, when stopped by an obstacle. Assuming that whole of the kinetic energy of bullet got converted into heat energy, calculate the velocity of the bullet. Given that initial temperature of the bullet = 47.6^(@)C . Melting point of lead 321^(@)C , specific heat of lead = 0.3 cal g^(-1).^(@)C^(-1) , latent heat of lead = 6 cal g^(-1) and J = 4.2 xx 10^(7) erg cal^(-1) .

A hunter fired a metallic bullet of mass 'm' kg from a gun towards an obstacle and it just melts when it is stopped by the obstacle. The initial temperature of the bullet is 300 K . If 1/4 th of heat is absorbed by the obstacle, then the minimum velocity of the bullet is Melting point of bullet=600 K Specific heat of bullet = 0.03 cal g^-1^@C^-1 , Latent heat of fusion of bullet= 6 cal g^-1 ]